Changing the structure of a function with if statement Python

Question

There is the function a could either be in the form of client.LinearKline.LinearKline_get() or in the form of client.Kline.Kline_get(). How could I make a and b modular so that both options could work the function below does not really work.

if choice ==1:
    a= LinearKline
    b= LinearKline_get
else:
    a= Kline
    b= Kline_get

client.a.b()

score 3 · Accepted Answer · edited Apr 27 '21 at 19:47

3

you can also use getattr for this.

if choice == 1:
    a = "LinearKline"
    b = "LinearKline_get"
else:
    a = "Kline"
    b = "Kline_get"

getattr(getattr(client, a), b)()

edited Apr 27 '21 at 19:47

Pranav Hosangadi

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answered Apr 27 '21 at 19:43

jen

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5

actually instead of `a` and `b` could I write it as `a="LinearKline.LinearKline_get"`? – tony selcuk Apr 27 '21 at 19:52
@tonyselcuk why don't you try it yourself and tell us! – Pranav Hosangadi Apr 27 '21 at 19:53
I tried to do `getattr(client, a)()` but its giving me an error – tony selcuk Apr 27 '21 at 20:11
maybe because ```a``` might not be a function. – jen Apr 27 '21 at 20:13
`a` is `a` and `b` combined your function works I am just trying to make it simpler. – tony selcuk Apr 27 '21 at 20:45

score 1 · Answer 2 · answered Apr 27 '21 at 19:44

1

If you have access to the client variable you can directly pick the function you need to call:

if choice == 1:
    f = client.LinearKline.LinearKline_get
else:
    f = Kline.Kline_get

f()

answered Apr 27 '21 at 19:44

quamrana

37,849
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Changing the structure of a function with if statement Python

2 Answers2

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