Slicing a list with another list

Question

I have a list that like:

list = ['a', 'b', 'c', 'd', 'e']

I want to slice, selecting 'a', 'c', 'd'. I try doing:

list[0, 2, 3]

and I receive an error message that says: 'list indices must be integers or slices, not tuple'.

I also tried:

list[True, False, True, True, False]

and I receive an error message that says: 'list indices must be integers or slices, not list'.

Can anyone help me?

Regards

I don't believe this can be done as a slice, as the desired elements are irregular. Did you really want a _slice_? — John Gordon, Apr 28 '21 at 01:13
That is not a valid list slice ... Which is what the error is telling you. — juanpa.arrivillaga, Apr 28 '21 at 01:14

score 2 · Answer 1 · answered Apr 28 '21 at 01:07

2

slicedList = [list[0],list[2],list[3]]

answered Apr 28 '21 at 01:07

Smolakian

score 1 · Accepted Answer · answered Apr 28 '21 at 01:09

1

You can use list comprehension:

result = [list[q] for q in selection]

where selection is the list with the indices you want to extract.

As a general rule: do not used list as variable name as it overrides the builtin list()

answered Apr 28 '21 at 01:09

Christian K.

score 1 · Answer 3 · answered Apr 28 '21 at 01:13

1

try this:

li1 = ['a', 'b', 'c', 'd', 'e']
selected = ['a', 'c', 'd']
list(filter(lambda x:x in selected, li1))

answered Apr 28 '21 at 01:13

theabc50111

score 0 · Answer 4 · answered Apr 28 '21 at 01:05

0

from operator import itemgetter

i = itemgetter(0, 2, 3)
lst = ["a", "b", "c", "d", "e"]

print(i(lst))

Prints:

('a', 'c', 'd')

answered Apr 28 '21 at 01:05

Andrej Kesely

4 Answers4