Python dateutil parser fails

Question

I am attempting to parse the following date strings obtained from email headers:

from dateutil import parser
d1 = parser.parse('Tue, 28 Jun 2011 01:46:52 +0200')
d2 = parser.parse('Mon, 11 Jul 2011 10:01:56 +0200 (CEST)')
d3 = parser.parse('Wed, 13 Jul 2011 02:00:01 +0000 (GMT+00:00)')

The third one fails; am I missing something obvious?

have you tried `parser.parse('...', fuzzy=True)`? – phimuemue Jul 18 '11 at 08:03 — phimuemue, Jul 18 '11 at 08:03
phimuemue, add that as an answer and I will accept it! – Petter Jul 18 '11 at 08:06 — Petter, Jul 18 '11 at 08:06
eryksun, that is a good suggestion. – Petter Jul 18 '11 at 08:15 — Petter, Jul 18 '11 at 08:15

score 4 · Accepted Answer · answered Jul 18 '11 at 19:03

4

have you tried parser.parse('...', fuzzy=True)? (I suppose it works :))

answered Jul 18 '11 at 19:03

phimuemue

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Yes it works. The problem is the extra "+00:00" after "GMT", as pointed out below. The "fuzzy" option ignores this. – Petter Jul 19 '11 at 07:55

score 2 · Answer 2 · answered Jul 18 '11 at 09:14

2

Give a try to parsedatetime library.

In [16]: import parsedatetime.parsedatetime as pdt

In [17]: p = pdt.Calendar()

In [18]: p.parse("Wed, 13 Jul 2011 02:00:01 +0000 (GMT+00:00)")
Out[18]: ((2011, 7, 20, 0, 0, 0, 2, 201, -1), 3)

answered Jul 18 '11 at 09:14

Michał Bentkowski

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But is it correct? I have difficulty interpreting the tuple. Where is the "13", for example? – Petter Jul 19 '11 at 08:08
It seems that this parser is confused and thinks the "Wed" refers to tomorrow July 20, which is the closest Wednesday. – Petter Jul 19 '11 at 08:09
Looks like `parsedatetime` always takes future dates. it has a comment in the source code: `# if that day and month have already passed in this year, then increment the year by 1` – warvariuc Jan 10 '12 at 07:37

Python dateutil parser fails

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