Replace all instances of a character in a 2d numpy array

Question

I have a Numpy array like this:

   [[ a, b, c]
    [ d, d, e]
    [ d, f, g ]]

How would I go about replacing every instance of char d in this 2d array while keeping the shape of the array? Assuming temp is our 2d array, I tried this but it did not work:

for i in range(len(temp)):
        temp[i].replace('d','')

@juanpa.arrivillaga I think what OP gave there is an MRE already. The attempted code didn’t run for the obvious reason, but IMHO, that’s good enough. — Quang Hoang, Apr 28 '21 at 21:35

score 1 · Accepted Answer · answered Apr 28 '21 at 21:32

1

Assuming temp as a numpy array, try update with indexing

temp[temp=='d'] = ''

answered Apr 28 '21 at 21:32

Quang Hoang

146,074
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score 0 · Answer 2 · answered Apr 28 '21 at 21:35

0

You can just use slice it on a boolean index and set the value.

import numpy as np

x = np.array([[ 'a', 'b', 'c'],
    [ 'd', 'd', 'e'],
    [ 'd', 'f', 'g' ]]
)

x[x=='d'] = 'z'

answered Apr 28 '21 at 21:35

James

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4
47
70

Replace all instances of a character in a 2d numpy array

2 Answers2