Javascript Regex multiple search in two words

Question

I want to transfer the results between Regex and two words to an array, but unfortunately I couldn't this. Can you help me?

In this text

[row]
Row text1
[rowEnd]

[row]
Row text2
[rowEnd]

I will search this content,

[row]
(.*)
[rowEnd]

Based on this I write a regex like this

/(\[row\]+)(.*)(\[rowEnd\])/gs

However, this way, it takes the whole, not piece by piece.

Thank you in advance for your help.

The fourth bird · Accepted Answer · 2021-05-02T10:42:01.883

4

In Javascript, you could use

^\[row]\r?\n([^]*?)\r?\n\[rowEnd]

^ Start of string
\[row]\r?\n Match [row] and a newline
( Capture group 1
- [^]*? Match 0+ times any char including a newline non greedy
) Close group 1
\r?\n\[rowEnd] Match a newline and [rowEnd]

Regex demo

const regex = /^\[row]\r?\n([^]*?)\r?\n\[rowEnd]/gm;
const str = `[row]
Row text1
[rowEnd]

[row]
Row text2
[rowEnd]`;

Array.from(str.matchAll(regex), m => console.log(m[1]));

edited May 02 '21 at 10:42

answered May 02 '21 at 10:37

The fourth bird

154,723
16
55
70

1

Awesome! I didn't know about `[^]`. Every time I come across your answers on [tag:regex], I learn something new. Keep it up! – Arvind Kumar Avinash Nov 30 '22 at 18:53

score 1 · Answer 2 · answered May 02 '21 at 10:45

1

Without RegEx

Split the data by "[row]".
Then filter those strings which end with "[rowEnd]".
Finally remove "[rowEnd]" from the filtered strings.

const 
  data = "[row]Row text1[rowEnd][row]Row text2[rowEnd]",
  res = data
    .split("[row]")
    .filter((s) => s.endsWith("[rowEnd]"))
    .map((s) => s.slice(0, -8));

console.log(res);

answered May 02 '21 at 10:45

Som Shekhar Mukherjee

4,701
1
12
28

As another way this works too. Thanks! – Emin TAYFUR May 02 '21 at 11:01

Javascript Regex multiple search in two words

2 Answers2

Without RegEx