How i can get the position of 4,3,6 present in this order in one array?
import numpy as np
# This is where i want find the position of the series
# as you can see the series are
# here here here
a = np.array([5,6,7, 5,4,7, 3,6,7, 4,3,6 ,1,2,3, 4,5,6, 4,3,6, 9,3,2, 3,4,4, 4,3,6])
The result i would is:
[9 , 18 , 27 ]
my first solution is :
#the series i'm looking for
se=[4,3,6]
#where append the results
r = []
for i in range(len(a)-2):
if a[i+0] == se[0] and a[i+1] == se[1] and a[i+2] == se[2]:
r.append(i)
print(r)
output:
[9,18,27]
How i can obtain this result in a fast way with large 'a' array?
Thanks to all .
