How to print the input as an integer, float or string in Python

Question

The purpose of my code is for the output to give the number and the type of the input. For instance:

If the input is: 10

The output should be: 10 is an integer

If the input is: 10.0

The output should be: 10.0 is a float

If the input is: Ten

The output should be: Ten is a string

I am quite a beginner with programming so I don't know any "advanced" functions yet. I shouldn't have to use it either because this is a starting school assignment. Normally I should be able to solve this with if, elif and else statements and maybe some int (), float () and type () functions.

x = input("Enter a number: ")

if type(int(x)) == int:
    print( x, " is an integer")
elif type(float(x)) == float:
    print( x, "is a float")
else:
    print(x, "is a string")

However, I keep getting stuck because the input is always given as a string. So I think I should convert this to an integer / float only if I put this in an if, elif, else statements, then logically an error will come up. Does anyone know how I can fix this?

Checkout [Python, Determine if a string should be converted into Int or Float](https://stackoverflow.com/questions/15357422/python-determine-if-a-string-should-be-converted-into-int-or-float) — DarrylG, May 07 '21 at 09:41
Does this answer your question? [Python, Determine if a string should be converted into Int or Float](https://stackoverflow.com/questions/15357422/python-determine-if-a-string-should-be-converted-into-int-or-float) — AMC, May 07 '21 at 14:48

ThePyGuy · Accepted Answer · 2021-05-07T09:57:42.273

REMEMBER: Easy to ask forgiveness than to ask for permission (EAFP)

You can use try/except:

x = input("Enter a number: ")
try:
    _ = float(x)
    try:
        _ = int(x)
        print(f'{x} is integer')
    except ValueError:
        print(f'{x} is float')
except ValueError:
    print(f'{x} is string')

SAMPLE RUN:

x = input("Enter a number: ")
Enter a number: >? 10
10 is ineger

x = input("Enter a number: ")
Enter a number: >? 10.0
10.0 is float

x = input("Enter a number: ")
Enter a number: >? Ten
Ten is string

score 0 · Answer 2 · answered May 07 '21 at 09:46

0

Since it'll always be a string, what you can do is check the format of the string:

Case 1: All characters are numeric (it's int)

Case 2: All numeric characters but have exactly one '.' in between (it's a float)

Everything else: it's a string

answered May 07 '21 at 09:46

FrancisRCuenca

11
2

DarrylG · Answer 3 · 2021-05-07T09:56:47.837

You can use:

def get_type(x):
    ' Detects type '
    if x.isnumeric():
        return int      # only digits
    elif x.replace('.', '', 1).isnumeric():
        return float    # single decimal
    else:
        return None

# Using get_type in OP code
x = input("Enter a number: ")

x_type = get_type(x)
if x_type == int:
    print( x, " is an integer")
elif x_type == float:
    print( x, "is a float")
else:
    print(x, "is a string")

Example Runs

Enter a number: 10
10  is an integer

Enter a number: 10.
10. is a float

Enter a number: 10.5.3
10.5.3 is a string

How to print the input as an integer, float or string in Python

3 Answers3

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