my xhr status return allways 200 however in my condition if it does not take it into account

Question

I have a problem with my xhr. The xhr status returns always 200. However, in my condition if it does not take it into account.

In the condition it goes directly to the else while the xhr.status returns the response 200. In the condition I put an if the response was 200 then it was using this :

console.log ('hello');

However, he sends this back to me

console.log ('salut');

My code :


var XMLHttpRequest = require('node-http-xhr');
 

global.XMLHttpRequest = require('node-http-xhr');


var url = "https://www.google.com/";

var xhr = new XMLHttpRequest();
xhr.open("GET", url);

xhr.setRequestHeader("User-Agent", "Mozilla/5.0 (Windows NT 6.3; Win64; x64; rv:88.0) Gecko/20100101 Firefox/88.0");
xhr.setRequestHeader("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8");
xhr.setRequestHeader("Accept-Language", "en-US,en;q=0.5");
xhr.setRequestHeader("Connection", "keep-alive");
xhr.setRequestHeader("Upgrade-Insecure-Requests", "1");

xhr.onreadystatechange = function () {
   if (xhr.readyState === 4) {
     console.log(xhr.status);
   }};


xhr.send();

if(xhr.status == 200){
  console.log('bonjour');
  }else{
    console.log('salut');
    
  }

Does this answer your question? [How do I return the response from an asynchronous call?](https://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call) — SuperStormer, May 08 '21 at 22:03

Đăng Khoa Đinh · Accepted Answer · 2021-05-08T22:23:27.103

0

You don't have the response of your request right after the line xhr.send(). The result is available in the onreadystatechange function. So, you need to move your condition into this function.

Change from :

xhr.onreadystatechange = function () {
   if (xhr.readyState === 4) {
     console.log(xhr.status);
}};

xhr.send();

if(xhr.status == 200) {
  console.log('bonjour');
} else {
  console.log('salut');  
}

to :

xhr.onreadystatechange = function () {
   if (xhr.readyState === 4) {
     console.log(xhr.status);
   }

   // move the condition here
   if(xhr.status == 200) {
      console.log('bonjour');
   } else {
     console.log('salut');
   }
};

xhr.send();

edited May 08 '21 at 22:23

answered May 08 '21 at 22:17

Đăng Khoa Đinh

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this good but this launch 3 time again on the console. you know why – x_zone web May 08 '21 at 22:36
If you found my answer helpful, you can upvote or mark it as accepted :) – Đăng Khoa Đinh May 09 '21 at 08:02
ahahaha really help full ;) if you want you can help me again with my other topic https://stackoverflow.com/questions/67454605/click-on-checkbox-using-puppetter – x_zone web May 09 '21 at 08:31

my xhr status return allways 200 however in my condition if it does not take it into account

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