I am trying to draw two graphs using chartjs. I want to make my life simplier by using a for loop
to declare the variables required for the chart object.
The thing is I have created a 2d array, with each row storing data for current year, the next row storing data for the consecutive year and so on. I am trying to access the row of the variable using loop.
Here is my Chart obj
var canvas6= {
type: 'doughnut',
data: {
datasets: [{
data: [
<?php
for($i=0;$i<count($dataAgeGrp[1]);$i++){ -------->Note here
echo $dataAgeGrp[1][$i]; -------->And here
echo ',';
}
?>
],
backgroundColor: [
<?php
for($i=0;$i<count($ageCategory);$i++){
$rand = str_pad(dechex(rand(0, 0xFFFF00)), 6, 0, STR_PAD_LEFT);
echo('"#' . $rand.'"');
echo ",";
}
?>
],
label: 'Pie Chart'
}],
labels: [
<?php
for($i=0;$i<count($ageCategory);$i++){
echo $ageCategory[$i];
echo ',';
}
?>
],
},
options: {
responsive: true
}
};
$(function () {
var ctx126 = document.getElementById('canvas6').getContext('2d');
window.myPie = new Chart(ctx126 , canvas6);
});
So, I tried something like this
for(var k=0;k<3;k++){
var q=26;
var canvas+q = {
type: 'doughnut',
data: {
datasets: [{
data: [
<?php
for($i=0;$i<count($dataAgeGrp[k]);$i++){
echo $dataAgeGrp[k][$i];
echo ',';
}
?>
],
backgroundColor: [
<?php
for($i=0;$i<count($ageCategory);$i++){
$rand = str_pad(dechex(rand(0, 0xFFFF00)), 6, 0, STR_PAD_LEFT);
echo('"#' . $rand.'"');
echo ",";
}
?>
],
label: 'Pie Chart'
}],
labels: [
<?php
for($i=0;$i<count($ageCategory);$i++){
echo $ageCategory[$i];
echo ',';
}
?>
],
},
options: {
responsive: true
}
};
$(function () {
var ctx1+q = document.getElementById('canvas'+q).getContext('2d');
window.myPie = new Chart(ctx1+q , canvas+q);
});
q=q+1;
But I am getting this error
Use of undefined constant k - assumed 'k' (this will throw an Error in a future version of PHP)
How do I fix it?