Variable Wrongly Passes Through Elif Statement (Python 3)

Asked May 13 '21 at 19:47

Active May 13 '21 at 19:53

Viewed 11 times

thing = 'window'

if 'table' or 'chair' in thing.lower().split():
        print('AHHHHHH I HATE THIS SO MUCH')

For some reason the statement is printed, even though 'table' or 'chair' are clearly not in the variable. Why does this happen?

edited May 13 '21 at 19:53

asked May 13 '21 at 19:47

Wiiat

Basically same thing as [this](https://stackoverflow.com/questions/20002503/why-does-a-x-or-y-or-z-always-evaluate-to-true) and [this](http://stackoverflow.com/questions/15112125/how-do-i-test-one-variable-against-multiple-values). – ForceBru May 13 '21 at 19:54
because `'table' or 'chair' in thing.lower().split()` is always true, it. is equivalent to `('table') or ('chair' in thing.lower().split())` so regardless of what happens with `'chair' in thing.lower().split())`, `'table'` always evaluates to true since it is a non-empty string – juanpa.arrivillaga May 13 '21 at 19:59

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