PHP Sort Sub-Array of Sub-Array

Question

I have seen other examples, such as:

PHP Sort Array By SubArray Value

The responses there were great, and I expect to incorporate the sortBySubValue part of the solution proposed by @Pigalev Pavel.

In my use case though, I have an extra level of sub-array, and when I pass in my array, it does not get sorted...

My array structure is:

$players = array(
    array(
        "name" => "Woods",
        "countback" => array(
            "9" => 17,
            "6" => 11,
            "3" => 6,
            "1" => 2
        )
    ),
    array(
        "name" => "Spieth",
        "countback" => array(
            "9" => 17,
            "6" => 12,
            "3" => 4,
            "1" => 2
        )
    ),
    array(
        "name" => "McIlroy",
        "countback" => array(
            "9" => 17,
            "6" => 12,
            "3" => 5,
            "1" => 1
        )
    ),
    array(
        "name" => "Johnson",
        "countback" => array(
            "9" => 17,
            "6" => 12,
            "3" => 5,
            "1" => 2
        )
    )
);

Where the parent array is sorted by the order of the countback sub-array. The expected final order should be:

1. Johnson, winner because the 4th array value (2) is highest in final comparison
2. McIlroy, 2nd as the 4th array value (1) is lower
3. Speech, 3rd as the 3rd array value (4) is lower than the remainders
4. Woods, lowest as 2nd array value (11) is lower than the others.

What changes need to be made to the function provided by @Pigalev Pavel?

/**
 * @param array $array
 * @param string $value
 * @param bool $asc - ASC (true) or DESC (false) sorting
 * @param bool $preserveKeys
 * @return array
 * */
function sortBySubValue($array, $value, $asc = true, $preserveKeys = false)
{
    if (is_object(reset($array))) {
        $preserveKeys ? uasort($array, function ($a, $b) use ($value, $asc) {
            return $a->{$value} == $b->{$value} ? 0 : ($a->{$value} <=> $b->{$value}) * ($asc ? 1 : -1);
        }) : usort($array, function ($a, $b) use ($value, $asc) {
            return $a->{$value} == $b->{$value} ? 0 : ($a->{$value} <=> $b->{$value}) * ($asc ? 1 : -1);
        });
    } else {
        $preserveKeys ? uasort($array, function ($a, $b) use ($value, $asc) {
            return $a[$value] == $b[$value] ? 0 : ($a[$value] <=> $b[$value]) * ($asc ? 1 : -1);
        }) : usort($array, function ($a, $b) use ($value, $asc) {
            return $a[$value] == $b[$value] ? 0 : ($a[$value] <=> $b[$value]) * ($asc ? 1 : -1);
        });
    }
    return $array;
}

If I print_r($players); at the end of my PHP script, the array remains in the original order.

UPDATE & RESOLVED Following comments provided, the issue was that I have printed the original array ($players), without allowing the function to update the original variable (by reference). the other option is to store it in a new variable returned by the function itself, as:

$sortedPlayers = sortBySubValue($players, 'countback', false);