2

I have a df

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I have to find all the combinations of Group (let's say 2 pairs) and then have to group them across unique ID's

Output:

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Currently I found a way to generate all the combinations but cannot seem to group by unique ID's

I referred to below links as well: Pandas find all combinations of rows under a budget

Code to generate the pairs:

from itertools import combinations
li_4 =[]
for index in list(combinations(df.group.unique(),2)):
       li_4.append([index[0],index[1]])
Akshat Shreemali
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1 Answers1

2

We can do merge then np.sort and pass the result to crosstab after remove the duplicate with drop_duplicates

s = df.merge(df,on='Id')
s['New'] = list(map(lambda x : ''.join(x),np.sort(s[['Group_x','Group_y']].values,axis=1).tolist()))
s = s.drop_duplicates(['Id','New'])
s = pd.crosstab(s.Id,s.New)
s
Out[88]: 
New  aa  ab  ac  ad  af  bb  bc  bd  be  bf  cc  cd  dd  de  ee  ff
Id                                                                 
2     1   1   1   1   0   1   1   1   0   0   1   1   1   0   0   0
3     0   0   0   0   0   1   0   1   1   0   0   0   1   1   1   0
4     1   1   0   0   1   1   0   0   0   1   0   0   0   0   0   1
BENY
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