OnLongPressGesture release action (SwiftUI)

Question

I see there is a .onLongPressGesture(minimumDuration:maximumDistance:pressing:perform:).

However there isnt enough documentation for me to understand how to perform an action when the user releases the button.

A good example to understand what I am talking about is when you hold down a button to start recording a video and let go to stop the recording.

.onLongPressGesture(minimumDuration: 0.5, maximumDistance: 100, pressing: {}, perform: {} )

What if you just add `onTapGesture` to the `Button` in addition to `onLongPressGesture`? Also, I believe the `label` parameter is a `Label`, not a string. I believe you're looking for `Button(_:action:)`. — West1, May 19 '21 at 15:18
Does this answer your question https://stackoverflow.com/a/60465960/12299030? Or this one https://stackoverflow.com/a/61723144/12299030? — Asperi, May 19 '21 at 15:30
Check this out: https://stackoverflow.com/a/61784292/14351818 — aheze, May 19 '21 at 16:31
@BestFromAbove It was certainly relevant when I posted it (before you edited your question to exclude your incorrect use of `Button`). — West1, May 19 '21 at 17:19
@West1 Pointing out an incorrect label argument has no relevance to the question of an onLongPressGesture modifier. — , May 20 '21 at 13:55
@BestFromAbove 1) I regret trying to help you, lol. 2) Your code was never going to work as it was, so pointing this out was *absolutely* relevant. 3) In the future, you should test your code in Xcode before pasting it into Stack Overflow so you avoid making another stupid mistake. — West1, May 20 '21 at 14:29

score 2 · Accepted Answer · answered May 19 '21 at 16:52

The answer to this is by calling the identifier like this.

Created a state that tracks if the user has pressed the button

@State var hasPressed = false

On the pressing parameter, use the state to perform an action depending on if the user is pressing the button or not.

.onLongPressGesture(minimumDuration: 0.5, maximumDistance: 100, pressing: {
                            pressing in
                            self.hasPressed = pressing
                            if pressing {action1}
                            if !pressing {action2}
                        }, perform: {})

OnLongPressGesture release action (SwiftUI)

1 Answers1