Python Common Word List with Frequency Greater than 1

Question

Suppose I've a list here:

list = ['cat', 'dog', 'wolf', 'cat', 'wolf', 'cat', 'sheep', 'sheep']

I want to fetch only those words from which are having common frequency greater than 1.

Resultant list should be:

['cat', 'wolf', 'sheep']

Can anyone help me with this?

`'wolf'` doesn't have a frequency greater than 2 – Cireo May 19 '21 at 19:26 — Cireo, May 19 '21 at 19:26

score 2 · Accepted Answer · answered May 19 '21 at 19:28

You can use collections.Counter to count the number of repetitions, then use a list comprehension to keep only those with a count greater than 1.

>>> from collections import Counter
>>> words = ['cat', 'dog', 'wolf', 'cat', 'wolf', 'cat', 'sheep', 'sheep']
>>> c = Counter(words)
>>> [k for k, v in c.items() if v > 1]
['cat', 'wolf', 'sheep']

score 1 · Answer 2 · answered May 19 '21 at 19:28

list = ['cat', 'dog', 'wolf', 'cat', 'wolf', 'cat']

items_map = {}
for item in list:
    if item not in items_map.keys():
        items_map[item] = 1
    else:
        items_map[item] += 1

result = []

for key in items_map.keys():
    if items_map[key] > 1:
        result.append(key)

print(result)

Python Common Word List with Frequency Greater than 1

2 Answers2