Selecting data from array, based on day of the week using PHP

Question

I have the following code, taken from another question:

<?php

$times = array(
    'mon' => '9:00 AM - 12:00 AM',
    'tue' => '9:00 AM - 12:00 AM',
    'wed' => '9:00 AM - 12:00 AM',
    'thu' => '9:00 AM - 12:00 AM',
    'fri' => '9:00 AM - 1:00 AM',
    'sat' => '9:00 AM - 1:00 PM, 2:00 PM - 1:00 AM',
    'sun' => 'closed'
);

function compileHours($times, $timestamp) {
    $times = $times[strtolower(date('D',$timestamp))];
    if(!strpos($times, '-')) return array();
    $hours = explode(",", $times);
    $hours = array_map('explode', array_pad(array(),count($hours),'-'), $hours);
    $hours = array_map('array_map', array_pad(array(),count($hours),'strtotime'), $hours, array_pad(array(),count($hours),array_pad(array(),2,$timestamp)));
    end($hours);
    if ($hours[key($hours)][0] > $hours[key($hours)][1]) $hours[key($hours)][1] = strtotime('+1 day', $hours[key($hours)][1]);
    return $hours;
}

function isOpen($now, $times) {
    $open = 0; // time until closing in seconds or 0 if closed
    // merge opening hours of today and the day before
    $hours = array_merge(compileHours($times, strtotime('yesterday',$now)),compileHours($times, $now)); 

    foreach ($hours as $h) {
        if ($now >= $h[0] and $now < $h[1]) {
            $open = $h[1] - $now;
            return $open;
        } 
    }
    return $open;
}

$now = strtotime('7:59pm');
$open = isOpen($now, $times);

if ($open == 0) {
    echo "Is closed";
} else {
    echo "Is open. Will close in ".ceil($open/60)." minutes";
}

?>

It is working as is, but i want to be able to output the schedule for the current day, for example:

The schedule for today (thu) is 9:00 AM - 12:00 AM

How can i do this? I understand that date('D') outputs the current day (Thu), but i have not been able to make it work to extract the desired data from the array.

What have you tried to make it work? Where are you stuck? What does "extract the desired data" mean? — Nico Haase, May 20 '21 at 08:10

score 2 · Accepted Answer · edited May 20 '21 at 09:07

2

The simplest solution as per your question is below, rest of the functions you can use or you can use according to your logic.

<?php
$times = array(
    'mon' => '9:00 AM - 12:00 AM',
    'tue' => '9:00 AM - 12:00 AM',
    'wed' => '9:00 AM - 12:00 AM',
    'thu' => '9:00 AM - 12:00 AM',
    'fri' => '9:00 AM - 1:00 AM',
    'sat' => '9:00 AM - 1:00 PM, 2:00 PM - 1:00 AM',
    'sun' => 'closed'
);
$data=date("D");
echo "The schedule for today (".strtolower($data).") is ".$times[strtolower($data)];
?>

edited May 20 '21 at 09:07

El_Vanja

3,660
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answered May 20 '21 at 08:13

Muhammad Asif

456
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Why call `strtolower()` twice? – mickmackusa Oct 06 '22 at 05:11

Selecting data from array, based on day of the week using PHP

1 Answers1