3

I need to apply a function to two lists. The map function is map :: (a->b) -> [a] -> [b], however I need something more like map2 :: (a->b->c) -> [a] -> [b] -> [c]. Is there a prelude function similar to map that can do this?

Will Ness
  • 70,110
  • 9
  • 98
  • 181
user15263733
  • 83
  • 4
  • 2
    you can find those easily with Hoogle (see [here](https://www.stackage.org/lts-17.13/hoogle?q=%28a+-%3E+b+-%3E+c%29+-%3E+%5Ba%5D+-%3E+%5Bb%5D+-%3E+%5Bc%5D)) - for example [`zipWith`](https://www.stackage.org/haddock/lts-17.13/base-4.14.1.0/Prelude.html#v:zipWith) – Random Dev May 26 '21 at 10:07

1 Answers1

9

You can find such function by hoogling (a -> b -> c) -> [a] -> [b] -> [c]. Yes, it's called zipWith.

snak
  • 6,483
  • 3
  • 23
  • 33