How to make a list of all possible permutations?

Question

Is there a function that generates all the permutations of a list of lists, while keeping their orders?

For example:

func([[1, 2, 3], [10, 20, 30]])

produces:

[[1, 10], [1, 20], [1, 30], [2, 10], [2, 20], [2, 30], [3, 10], [3, 20], [3, 30]]

What did you find so far when you searched for such a function? Have you seen the `itertools` module in the Python standard library already? — mkrieger1, May 30 '21 at 19:07
By the way, what you have shown as an example is called "cartesian product", not "permutations". — mkrieger1, May 30 '21 at 19:09

score 0 · Accepted Answer · answered May 30 '21 at 19:10

There is a product function in itertools module which does exactly that :

from itertools import product

lst = [[1, 2, 3], [10, 20, 30]]
res = [list(i) for i in product(*lst)]
print(res)

Because you want the inside items to be list as well, I used list(i) to convert the tuple which product gives into list.

Output:

[[1, 10], [1, 20], [1, 30], [2, 10], [2, 20], [2, 30], [3, 10], [3, 20], [3, 30]]

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