Match everything that's not a digit or white space at the end of a string

Question

I have a field that looks like this :

------->Total cash dispensed: 40000 MGA

I want to get only the "MGA" using regex but without using split

regex = r"Total cash dispensed:\s*([^ 0-9]*)"

The code I used to get anything that's not number or white space does not work, How do I fix this?

Can you please include some examples with the expected results in those cases? — mousetail, May 31 '21 at 14:29
So you want the last part of a string after the last space? Why use regex? Why not `s.rsplit(' ', 1)[-1]`? — Tomerikoo, May 31 '21 at 14:31
To answer your question in the title most simply: `[^ \d]+$` — Tomerikoo, May 31 '21 at 14:49

score 2 · Accepted Answer · answered May 31 '21 at 14:38

2

You might use a capture group:

\bTotal cash dispensed:\s*\d+\s+([A-Z]+)\b

\bTotal cash dispensed:\s* Match the text starting with a word boundary and followed by : and optional whitespace chars
\d+\s+ Match 1+ digits and 1+ whitespace chars
([A-Z]+) Capture group 1, match 1+ chars A-Z
\b A word boundary to prevent a partial match

Regex demo

import re
 
pattern = r"\bTotal cash dispensed:\s*\d+\s+([A-Z]+)\b"
s = "------>Total cash dispensed: 40000 MGA"
 
matches = re.search(pattern, s)
 
if matches:
    print(matches.group(1))

Output

MGA

answered May 31 '21 at 14:38

The fourth bird

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Just to clarify: `\d` is not the same as `[0-9]` :) Example: `re.match('\d', '١')` – Riccardo Bucco May 31 '21 at 14:44
2

@RiccardoBucco Right, [`(?a)\d` = `[0-9]`](https://ideone.com/Cvavwr) in Python 3. `\d` matches any Unicode digits by default. `re.ASCII` / `re.A` or `(?a)` can be used to make `\d` equal to `[0-9]`. – Wiktor Stribiżew May 31 '21 at 15:01

mousetail · Answer 2 · 2021-05-31T14:39:31.437

0

You can match anything except whitespace and digits with the following expression:

[^\s\d]+

"\s\" is whitespace, including spaces, tabs, and enters

"\d" is digits, same as [0-9] and some other numeric characters from other scripts

Example:

re.search('[^\s\d]+', '123 \t')
# -> No match

edited May 31 '21 at 14:39

answered May 31 '21 at 14:33

mousetail

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`\d` is not the same as `[0-9]` – Riccardo Bucco May 31 '21 at 14:37
1

Based on this source Riccardo is right: https://stackoverflow.com/questions/6479423/does-d-in-regex-mean-a-digit#6479605 – mousetail May 31 '21 at 14:41
`re.match('\d', '١')` – Riccardo Bucco May 31 '21 at 14:43

Match everything that's not a digit or white space at the end of a string

2 Answers2