How do I strip quotes out of a list of strings?

Question

Hello guys I am having some issue trying to split my list into multiple element, my problem is the following: I have a list like that:

list1 = ['"22.23.24.25"']

(basically this list should represent an IP address but never mind) the problem is that I want to delete the quotation mark currently into my list, ideally my list would like:

list1 = ['22.23.24.25']

I really don't know how to do it since I am a beginner in python so it would be great if anyone can help me.

Answer 1

Simple solution is use the str.replace method twice, to ensure that all types of the quotations are removed.

list1 = ['"22.23.24.25"', "'11.22.33.44'"]

list1 = [x.replace('"', '').replace("'", '') for x in list1]

print(list1)
['22.23.24.25', '11.22.33.44']

Answer 2

Replacing in all elements in a list:

a=[i.replace("\"","") for i in list1]

result:

['22.23.24.25']

this iterates over all elements in list1, performs an action on each and puts them into new list

Answer 3

Just for the collection:

list1 = ['"22.23.24.25"', "'11.22.33.44'", "11.22.33.44"]

new_list = "\n".join(list1).replace("\"","").replace("'","").split("\n")

print(new_list) # ['22.23.24.25', '11.22.33.44', '11.22.33.44']

1. Join the array in one long string.
2. Remove all quotes from the string.
3. Split the sting back into an array.

This is a quite common technique. And probably it works faster than a list comprehension.

Answer 4

list1 = ['"22.23.24.25"']
for i in range(len(list1)):
    x=list1[i].replace("\"","")

Answer 5

l1=['"10.40.30.40.50"']
for x in l1:
    s=str(l1[0])
    for n in s:
        value=s[1:len(s)-1]
print(value)

Just a another method.