Change a variable inside from a if statement so the stament isnt true Python

Asked Jun 04 '21 at 18:33

Active Jun 04 '21 at 18:39

Viewed 28 times

I have a loop that every 1 second calls a def() with a function that has an if statement, so I need that if that statement is true, to only execute it once, So I thought to multiply the variable so the if statment isn't true again, but I have an error.

i = 0
x = 0
def test():
    if i > x:
        print("i > x")
        x = i * 10


while 1:
    test()

    time.sleep(1)

Traceback (most recent call last):
  File "stackoverflow.py", line 14, in <module>
    dynamicStopLoss()
  File "stackoverflow.py", line 7, in dynamicStopLoss
    if i > x:
UnboundLocalError: local variable 'x' referenced before assignment

edited Jun 04 '21 at 18:39

Charles Duffy

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asked Jun 04 '21 at 18:33

LaCK CSGO

Provide the error as text, not an image. See [Why not upload images of code/errors when asking a question?](https://meta.stackoverflow.com/a/285557/14122) on [meta]. – Charles Duffy Jun 04 '21 at 18:34
In this case, the problem is that you're defining `x` as a global, but accessing it as a local. – Charles Duffy Jun 04 '21 at 18:35
Relevant - https://www.programiz.com/python-programming/global-keyword – user2864740 Jun 04 '21 at 18:35

Change a variable inside from a if statement so the stament isnt true Python

0 Answers0