Is it possible to add multiple inputs for one parameter in python

Question

I am trying to create a program where it takes in a list of numbers and then it will only take the even numbers and print it.

My problem is that I am trying to understand how to give it the list of numbers for it to take in to the parameter.

Here is my code:

def getEvens(NumList):
    NumList = []
    for num in NumList:
        if num % 2 == 0:
            print(num, end = ",")
getEvens(39,94,3,4,5,67) # <--- How can I make this all go to one parameter?

Does this answer your question? [Can a variable number of arguments be passed to a function?](https://stackoverflow.com/questions/919680/can-a-variable-number-of-arguments-be-passed-to-a-function) — Brian61354270, Jun 06 '21 at 00:15
The above dupe explains how to do what you want. The simpler, more usable way would just be to pass a list though: `getEvens([39,94,3,4,5,67])`. Also, get rid of `NumList = []`. That will break things. — Carcigenicate, Jun 06 '21 at 00:16

score 0 · Accepted Answer · answered Jun 06 '21 at 00:28

def getEvens(NumList):
    for num in NumList:
        if num % 2 == 0:
            print(num, end = ",")

getEvens([39,94,3,4,5,67])

Remove NumList = [] because this just overwrites the parameter with an empty list

wrap the number params in [] to make them into a list when calling the function

score 0 · Answer 2 · answered Jun 06 '21 at 01:25

There is a non-keyword argument called *args which lets you pass several values at a time. More details on args here

def getEvens(*nums):
    for num in nums:
        if num % 2 == 0:
            print(num, end = ",")

getEvens(39,94,3,4,5,67)

You can makes this more simple using filter function

nums = (39,94,3,4,5,67)

getEvens = list(filter(lambda x: x % 2 == 0, nums))

print(','.join(getEvens))

Is it possible to add multiple inputs for one parameter in python

2 Answers2