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Does useRef store address for variables?

const x = useRef(data);
const y = x;

I'll have two separate copies of data or one? What will be the memory consumption? What are the drawbacks of this method?

1 Answers1

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I assume you would like to use JS as some other languages (C ?) - but keep in mind that they are differences. Check this answer: https://stackoverflow.com/a/21457798

Your example looks like trying of copy useRef object. Before you go to useRef, remember how to copy objects in JS example here: What is the most efficient way to deep clone an object in JavaScript?

CodeJoe
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