I am requesting clarification on the use of sorted lambda for sorting dictionaries. I have referenced these posts 1 2 in making my code which works fine, but am interested in understanding how it actually works.
'Unf': {'idf': 0, 'den': 0.0},
'Ale': {'idf': 3.1179499062782403, 'den': 0.0041841004184100415},
'No ': {'idf': 3.1179499062782403, 'den': 0.008620689655172414},
One': {'idf': 3.1179499062782403, 'den': 0.005319148936170213},
'but': {'idf': 0, 'den': 0.0},
'Bio': {'idf': 0, 'den': 0.0},
'Wen': {'idf': 0, 'den': 0.0},
'Lar': {'idf': 0, 'den': 0.0},
'Ana': {'idf': 0, 'den': 0.0},
'Adv': {'idf': 0, 'den': 0.0}}
this is the sorting code
newdict = dict(sorted(values.items(), key=lambda item: (item[1]['idf'], item[1]['den']), reverse=True))
newdict = dict(sorted(values.items(), key=lambda item: (item[1][0], item[1][1]), reverse=True))
for item: (item[1]['idf'], item[1]['den'] what exactly is the [1] index referring to? is it referring to the values(my inner dictionary) returned by values.items?
If so, if i change the index to [0] I would be getting the dictionary key instead?
Additionally, how would I go about sorting this if I were to use operator.itemgetter instead?
Thank you very much for the help everyone!
