Selenium python, use css to select only two class

Question

Suppose I have an HTML that looks like this:

<div class="first second">
    Right!
</div>
<div class="first second third fourth">
    Wrong!
</div>
<div class="first second">
    Right!
</div>

If I try to locate the first and third div, using css:

driver.find_elements_by_class_name("first, second")

Instead of getting 2 elements in my list, I get all the three divs because the second one actually contains those classes and some others... How can I restrict it, to locate only the <div>s with:

class = "first second"

what is the tag you have that contains `first, second` third tag also contains the same thing. — cruisepandey, Jun 09 '21 at 16:43

score 1 · Answer 1 · answered Jun 09 '21 at 16:51

1

div[class = 'first second']

should work. Cause it is a exact match.

use it with CSS_SELECTOR

driver.find_elements(By.CSS_SELECTOR , "div[class = 'first second']")

answered Jun 09 '21 at 16:51

cruisepandey

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score 1 · Answer 2 · answered Jun 09 '21 at 17:00

1

You can use this if you need to get them via xpath:

driver.find_elements_by_xpath(".//div[@class='first second']")

answered Jun 09 '21 at 17:00

itronic1990

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Selenium python, use css to select only two class

2 Answers2