Having a generator is there a way to exhaust the generator without using list()?
This code sample will not print anything:
(print(i) for i in range(10))
It will only do so. If I "invoke" it with list
list((print(i) for i in range(10)))
This is the usual practice I know and which is at least to my knowledge a vastly used technique.
If executed in the REPL, the number 0-9 are printed as expected and I receive a list of 10 None.
This makes perfect sense, as print doesn't return anything. However the program needs to store all these Nones in a list only to throw them away just afterwards.
This is very wasteful and subverts the generator's intention not to create large memory peaks.
I can implement my own utility function, which doesn't have this issue:
def do(iterable):
for _ in iterable:
pass
do((print(i) for i in range(10)))
Is there a similar functionality in the stdlib, or do I need to use my own utility function?
I admit, this only makes sense, if a generator has side effects and I am not interested in the generated values like in this simple example.
