I've been trying to return an array in C. I'm mostly acquainted with Java (where it's comparatively easier to return an array).
This is what I'm trying to do right now:
#include <stdio.h>
#include <stdlib.h>
int * duplicates(int[],int);
int main() {
int arr[] = {3,5,6,5,9,5,10,11,3};
int n = sizeof(arr)/sizeof(arr[0]);
int * tempArray = duplicates(arr,n);
for (int i = 0; i < n; i++) {
printf("%d \t",tempArray[i]);
}
}
int * duplicates(int arr[], int n) {
int tempArray[n];
int r = 0;
int flag = 0;
for (int i = 0; i < n; i++) {
for (int j = i+1; j < n; j++) {
if (arr[i] == arr[j]) {
for(int k = 0; k < r; k++) {
if(arr[i] == tempArray[k]) {
flag = 1;
}
}
if (flag == 0) {
tempArray[r++] = arr[i];
flag = 0;
} else {
break;
}
}
}
}
return tempArray;
}
And this, to no surprise - crashes my program. How I can return an array in C, because that feels like a bare-minimum, something I should know before I can move further into the language.