capture C++0x flag inside the program

Question

Possible Duplicate:
GNU C++ how to check when -std=c++0x is in effect?

What I want to do is:

 #if defined(CPLUSPLUS_OXFLAG)
  //do something
 #else
  //do something else
 #endif

Now how can I capture -std=c++0x argument passed to the compiler(g++) to define my CPLUSPLUS_OXFLAG flag?

You could try something like `#if __cplusplus >= 201103L #define CPLUSPLUS_OXFLAG #endif`. — , Jul 22 '11 at 20:28
In standard C++0x, ["the macro __cplusplus will be set to a value that differs from (is greater than) the current 199711L"](http://www2.research.att.com/~bs/C++0xFAQ.html#0x). I'm not sure if the experimental C++0x GCC implementation will do that. — In silico, Jul 22 '11 at 20:33

score 2 · Accepted Answer · answered Jul 22 '11 at 20:28

2

The GCC documentation states that the preprocessor symbol __GXX_EXPERIMENTAL_CXX0X__ is defined when compiling with -std=c++0x.

answered Jul 22 '11 at 20:28

Praetorian

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score 2 · Answer 2 · answered Jul 22 '11 at 20:31

2

For GCC have a look at this:

__GXX_EXPERIMENTAL_CXX0X__

This macro is defined when compiling a C++ source file with the option -std=c++0x or -std=gnu++0x. It indicates that some features likely to be included in C++0x are available. Note that these features are experimental, and may change or be removed in future versions of GCC.

Find the reference here.

answered Jul 22 '11 at 20:31

Alok Save

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thanks... +1 for the reference – A. K. Jul 22 '11 at 20:34

score 1 · Answer 3 · answered Jul 22 '11 at 20:29

1

GCC defines __GXX_EXPERIMENTAL_CXX0X__ when std=c++0x is enabled.

answered Jul 22 '11 at 20:29

Peter Alexander

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capture C++0x flag inside the program

3 Answers3