I need replace variable php ->

Question

Hello I have this variable in php with data but in some pages I don't have it defined so I need to replace it with some data but my code doesn't work.

$item->restaurant->name

Try with:

$item->item_category->name = "Mi content replace";

But it does not work. What am I doing wrong? Thanks

pls include all _relevant_ code. we can't tell from the little you put here. Can you do a `print_r($item)` and show inyour question what the output is? — Kinglish, Jun 13 '21 at 23:20
_"it does not work"_ is not a problem description. Explain what is happening and what you expect to happen, and Include here the complete text of any error messages you see. — Tangentially Perpendicular, Jun 13 '21 at 23:25

score 2 · Accepted Answer · answered Jun 13 '21 at 23:35

2

Since PHP 7.0 you can use the null coalescing operator ??. Which tries to fetch your $variable or else default to something else.

$nameOrDefault = $item->restaurant->name ?? "Mi content replace";

Or in a blade context

<p>
    {{ $item->restaurant->name ?? "Mi content replace" }}
</p>

answered Jun 13 '21 at 23:35

mrhn

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You are amazing! Thank you so much! – Eduardo Rafael Jun 13 '21 at 23:52
How would you add html content for example: Mi content replace – Eduardo Rafael Jun 13 '21 at 23:53
1

To escape html content {!! $html !!} see https://stackoverflow.com/questions/29253979/laravel-display-html-with-blade – mrhn Jun 13 '21 at 23:56
But what if I don't want to use a variable and only enriched text, how would it be? Search but did not find. Thanks – Eduardo Rafael Jun 14 '21 at 00:02
Hmm what do you mean by enriched text? – mrhn Jun 14 '21 at 00:04
Example: {{ $item->item_category->name ?? "!!Mi content replace!!"}} – Eduardo Rafael Jun 14 '21 at 00:05
{!! $item->item_category->name ?? "Mi content replace" !!} you case is a little bit edgy, does this work? – mrhn Jun 14 '21 at 07:32

I need replace variable php ->

1 Answers1