Struct varies in memory size?

Question

Why is not 12 in the first case? Tested on: latest versions of gcc and clang, 64bit Linux

struct desc
{
    int** parts;
    int nr;
};

sizeof(desc); Output: 16

struct desc
{
    int** parts;
};

sizeof(desc); Output: 8

struct desc
{
    int nr;
};

sizeof(desc); Output: 4

score 8 · Accepted Answer · answered Jul 23 '11 at 14:05

8

The compiler is allowed to add padding between struct members to make processing more efficient. This padding varies by platform, compiler version etc. It's one of the things that make sending structs over the network impossible.

You can use offsetof to find out where exactly your compiler is adding paddings.

answered Jul 23 '11 at 14:05

cnicutar

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64bit -> 8 bytes -> change 4 bytes to 8 bytes -> 16 – zw324 Jul 23 '11 at 14:12
3

it's impossible with C Standard; C Standard not includes struct/pragma packing – user411313 Jul 23 '11 at 14:19

score 2 · Answer 2 · answered Jul 23 '11 at 16:18

As the previous answer indicated, the compiler is allowed to add padding. This is usually done because sometimes the hardware requires that certain data types must occur on certain memory boundaries. It looks like your system wants to put pointers on an 8-byte boundary.

The padding is at the end of the structure and is necessary so that each element in an array of struct desc will still be on an 8-byte boundary.

Struct varies in memory size?

2 Answers2

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