Split text into words ignoring the single quoted word in text in JavaScript

Question

I am trying to split text into words on the basis of space but I don't want to split words in single quotes into different words.

Here if you can see word 'fd f df' is converted into three words 'fd , f , df' but I want to get this as single word like 'fd f df'.

const str = `TEST = 'fd f df' AND Pitch = 444`
str.split(/\s+/)
// ["TEST", "=", "'fd", "f", "df'", "AND", "Pitch", "=", "444"]

Any help will be appreciated.

P.S : this quoted words could be repeated in text many time in any position.

Krzysztof Krzeszewski · Answer 1 · 2021-06-17T07:09:08.213

6

I recommend using regex, in the example below the first part of the regex matches anything between the quotes and the 2nd part of the regex matches anything but spaces

const str = `TEST = 'fd f df' AND Pitch = 444`

console.log(str.match(/('.*?'|[^\s]+)/g));

edited Jun 17 '21 at 07:09

answered Jun 17 '21 at 06:56

Krzysztof Krzeszewski

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This is great if there's only one quoted section, but won't work for _repeated_ quoted words. – Simon Brahan Jun 17 '21 at 06:59
fixed it, with the lazy quantifier, thanks for pointing that out – Krzysztof Krzeszewski Jun 17 '21 at 07:09
@KrzysztofKrzeszewski can you please update regex with lazy quantifier , I don't have that much good understanding of regex. Thanks – Muhammad Shafiq Jun 17 '21 at 07:44
I already did it's the `?` in the first part of the regex – Krzysztof Krzeszewski Jun 17 '21 at 07:45

Split text into words ignoring the single quoted word in text in JavaScript

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