Best way to check null for each part of an experssion in java

Question

So I have something that looks like this:

(String) loginResponse.getGroup().getAdditionalProperties().get(something);

and each and every component of the expression could return null. I want to avoid throwing an exception and checking if null after each call doesn't look like the best way to do it:

   temp= loginResponse.getGroup();
   if(temp!=null){
      temp= temp.getAdditionalProperties()
      if(temp!=null){
         temp.get(something)
      }
   }etc...

What's a better way to do this?

Thanks

Does this answer your question? [Check chains of "get" calls for null](https://stackoverflow.com/questions/3458451/check-chains-of-get-calls-for-null) (check the most voted answer) — jhamon, Jun 22 '21 at 07:24
yes, thank you! Apparently I couldn't find that on my own ^^' — Ferran Veciana Buixeda, Jun 22 '21 at 07:34
Wow, whoever flagged this as duplicate to another question that has no actual solution really did a bad job. Thanx but no thanx. — JayC667, Jun 22 '21 at 07:44

score 0 · Answer 1 · answered Jun 22 '21 at 07:25

you can use "Optional" and chain the call inside a map()

Optional.ofNullable(toto).map(A::getB).map(B::getC).orElseThrow(...)
Optional.ofNullable(toto).map(A::getB).map(B::getC).orElseGet(...)

You avoid nullPointerException by this way. It goes in the orElse... if anly element is null at any places

Best way to check null for each part of an experssion in java

1 Answers1