How to assign very large numbers to variable in java?

Question

I'm getting "integer number too large: 1000000000001" for the following code line. How do I make it so that maxValue can hold 1 quadrillion or 1 trillion?

long maxValue = 1000000000001;      //1,000,000,000,001

Ted Hopp · Answer 1 · 2011-07-24T19:51:55.653

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You need to use a long literal (with an L at the end):

long maxValue = 1000000000001L; //1,000,000,000,001

Note that you don't need to use BigInteger if your numbers are between -2⁶³ and 2⁶³-1 (inclusive). (2⁶³-1 = 9223372036854775807L = 0x7fffffffffffffffL.)

edited Jul 24 '11 at 19:51

answered Jul 24 '11 at 18:47

Ted Hopp

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Actually `2^63` = 9 223 372 036 854 775 808 (10) = 8000000000000000 (16). Max value is `2^63 - 1` (because of two's complement binary representation). – Grzegorz Szpetkowski Jul 24 '11 at 19:00

score 1 · Answer 2 · answered Jul 04 '17 at 10:23

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This answer is complete.

Java Language Specification:

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).

answered Jul 04 '17 at 10:23

Alireza Noorali

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score 0 · Answer 3 · edited May 23 '17 at 11:43

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You may check for another question and answer before you ask. Someone probably has the same question and got the best answer. See this:

Large Numbers in Java

This is probably what you need.

edited May 23 '17 at 11:43

Community

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answered Jul 24 '11 at 18:48

Kristiono Setyadi

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The question you linked to had as solution to use BigInteger. That's not needed in this case. – Ted Hopp Jul 24 '11 at 19:53

How to assign very large numbers to variable in java?

3 Answers3