I have a list like this, with an even number of elements:
straight_list = [1, 2, 3, 4, 5, 6]
There are six items in this list. I'd like to group them into three pairs, like this:
paired_list = [(1, 2), (3, 4), (5, 6)]
What's the best way to do this? More generally, given a list with 2*n items, what's the best way to create a list of n pairs? I have come up with the following:
straight_list = [1, 2, 3, 4, 5, 6]
paired_list = []
for i in range(len(straight_list)//2):
j = i*2
pair = (straight_list[j], straight_list[j+1])
paired_list.append(pair)
print(paired_list)
# [(1, 2), (3, 4), (5, 6)]
I also can make it work like this, though it's a tongue-twister:
[tuple(x) for x in list(np.array(straight_list).reshape(len(straight_list)//2,2))]
# [(1, 2), (3, 4), (5, 6)]
Is there a more elegant, functional, and/or "Pythonic" way to create this list of pairs?
(In some ways, this is almost an inverse of this question: "How to make a flat list out of a list of lists?")
