Grep and use results in Bash Script

Question

Since I am new in Bash language, I was trying to make a simple script to find the apache2 PHP Config File (php.ini) in Ubuntu and echo a new line into it.

I have used the this code to find the currently used php.ini :

#!/bin/sh

php -i | grep "Loaded Configuration File"       && \
echo "zend_extension=/path/extension.so" > PHP.INI_GREPPED       && \
// The rest of my Code

So, Instead of the (PHP.INI_GREPPED) I want to use the found php.ini file in the previous command.

The output of (php -i | grep "Loaded Configuration File) Shows this:

Loaded Configuration File => /etc/php/7.4/cli/php.ini

I want to only take (/etc/php/7.4/cli/php.ini) to echo a new line into it.

Also, IS it possible to change the file path before echo into it? for example, the output of the grep command was:

 Loaded Configuration File => /etc/php/7.4/cli/php.ini

and I want to change the echo into :

/etc/php/7.4/apache2/php.ini

NOTE: 7.4 may change depending on the installed version of PHP.

Anyway to do that? sorry I am new to bash.

You’re mixing sh and Bash. Pick one, they’re not the same. — Biffen, Jun 24 '21 at 07:25
@BHappy : Please indicate how you actually call your script. — user1934428, Jun 24 '21 at 07:58

score 1 · Accepted Answer · answered Jun 24 '21 at 07:35

1

Use sed:

php -i | grep Loaded\ Configuration\ File | sed 's/.*=> //'

And without grep:

php -i | sed -n '/^Loaded Configuration File/s/.*=> //p'

answered Jun 24 '21 at 07:35

ceving

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Got you .. Thanks for that.. it works – B Happy Jun 24 '21 at 08:06
can I make a variable with the path only? without php.ini ? to be like this: /etc/php/7.4/cli/ – B Happy Jun 24 '21 at 08:20
`p="$(php -i | grep Loaded\ Configuration\ File | sed 's/.*=> //')"` – ceving Jun 24 '21 at 08:23
The last command will make p as variable with the value (/etc/php/7.4/cli/php.ini). What I want is to make this variable: p = /etc/php/7.4/cli/ .. without php.ini – B Happy Jun 24 '21 at 08:27
`d="$(dirname "$(php -i | grep Loaded\ Configuration\ File | sed 's/.*=> //')")"` – ceving Jun 24 '21 at 10:10
You should consider reading a [UNIX tutorial](http://www.ee.surrey.ac.uk/Teaching/Unix/). – ceving Jun 24 '21 at 10:13

Grep and use results in Bash Script

1 Answers1