Replace multiple values in json during run time

Question

Old JSON File:

{
"firstName": "Rajesh",
"lastName": "Kumar",
"gender": "man",
"age": 24,
"address": {
    "streetAddress": "126 Udhna",
    "city": "Surat",
    "state": "GJ",
    "postalCode": "394221"
},
"phoneNumbers": [
    { "type": "home", "number": "7383627627" }
]
}

New Should be:

{
"firstName": "Raghunath",
"lastName": "Dhara",
"gender": "man",
"age": 25,
"address": {
    "streetAddress": "126 Udhna",
    "city": "Surat",
    "state": "GJ",
    "postalCode": "394221"
},
"phoneNumbers": [
    { "type": "home", "number": "7383627627" }
]
}

Please help me to replace multiple values in JSON file. I am struggling with this since 7 days.

See: [change json file by bash script](https://stackoverflow.com/q/24942875/3776858) — Cyrus, Jun 24 '21 at 18:13

score 2 · Answer 1 · answered Jun 24 '21 at 18:11

2

jq --arg first Raghunath --arg last Dhara --arg age 25 '.firstName = $first | .lastName = $last | .age = $age' file.json

answered Jun 24 '21 at 18:11

glenn jackman

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I would like to use variables where – Raghunath Dhara Jun 25 '21 at 12:13
So do that: `jq --arg first "$newFirstName" ...` – glenn jackman Jun 25 '21 at 13:38

Replace multiple values in json during run time

1 Answers1