Getting to know if '*' is included in a string?

Question

I have a string variable and I want to know if the multiplication symbol is in the string. This is what I did:

const str = "45*33"
const arr = str.split('')
if(arr.includes("*"){
console.log("Symbol found!")
}
else{
console.log("Error")
})

This does not work, is there a way I can make this work?

Does this answer your question? [How to check whether a string contains a substring in JavaScript?](https://stackoverflow.com/questions/1789945/how-to-check-whether-a-string-contains-a-substring-in-javascript) — enzo, Jun 27 '21 at 20:41
Also you can check https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf — Teoman shipahi, Jun 27 '21 at 20:41

score 1 · Answer 1 · answered Jun 27 '21 at 20:41

1

You don't need to split at all; you can directly use String#includes.

const str = "45*33";
if (str.includes("*")) {
    console.log("Symbol found!")
} else {
    console.log("Error")
}

answered Jun 27 '21 at 20:41

Unmitigated

76,500
11
62
80

score 0 · Answer 2 · answered Jun 27 '21 at 20:47

0

Use the console of your browser to check for errors. It is a simple syntax error at:

if(arr.includes("*"){

should be:

if(arr.includes("*")){

answered Jun 27 '21 at 20:47

coldgas

83
4

score 0 · Answer 3 · answered Jun 27 '21 at 21:14

Working perfectly now, it was a typo in the code that my eye just did not see. There is a reason why I had to split the string to an array. I could have just used the str.includes().

const str = "45*33"
const arr = str.split('')
if(arr.includes("*")){
console.log("Symbol found!")
}
else{
console.log("Error")
})

Thank you.

Getting to know if '*' is included in a string?

3 Answers3