python pass multiple arguments to many functions

Question

I can do:

myfun(a=1, b=2,c=3,d=4)
myfun(a=2, b=2,c=3,d=4)
myfun(a=1000, b=2,c=3,d=4)

But is there a way to store b,c,d and pass just one object to the function? Changing the value to any of b,c,d is costly, since I need to change it in many places.

I want something like this pseudocode:

args = (b=2, c=3, d=4)
myfun(a=1, **args)

Almost! Make `args` a dict: `{'b': 2, ...}`. – deceze Jul 01 '21 at 10:13 — deceze, Jul 01 '21 at 10:13

score 1 · Accepted Answer · answered Jul 01 '21 at 10:14

1

Your pseudocode is close to be true:

args = dict(b=2, c=3, d=4)
myfun(a=1, **args)

answered Jul 01 '21 at 10:14

Artem Mashkovskiy

131
3

python pass multiple arguments to many functions

1 Answers1