Going inside if condition where it should not

Question

My if condition in Python is not working. It is going inside the condition but it should not. Below is the code snippet:

a = np.nan

if a is not None :
   a = "".join(a)

The code is going inside the if condition and I don't know why.

`np.nan is not None` trivially and by definition. Why do you expect otherwise? Do you understand what `is` means in Python? — tripleee, Jul 07 '21 at 07:05

score 0 · Answer 1 · answered Jul 07 '21 at 07:05

0

np.nan is not a type of None. You can check it by using type(np.nan), which returns <class 'float'>.

np.nan is a class, it is not a None

answered Jul 07 '21 at 07:05

1

`np.nan` is not a class. It is an instance of a class; but then so is None. – khelwood Jul 07 '21 at 08:01

1 Answers1