python round numbers to specific value

Question

I would like to write a specif rounding logic.

number = x

if x < 950:
    # round number to and in steps of 50
elif x < 9000:
    # round number to and in steps of 100
elif x < 100000:
    # round number to and in steps of 250
else:
    # round number to and in steps of 1000

This is my idea how it could work.

What I need for example, if x = 123 then the it should be rounded to 100. if x = 170 it should be rounded to 200, and then for example for x = 8568 it should round to 8600

Something like `round(8568/100)*100` or `round(170/50)*50` ? — obchardon, Jul 07 '21 at 09:26
Is `x` always an integer? Which direction should halfway-cases round (e.g., `825` or `1350`)? — Mark Dickinson, Jul 07 '21 at 14:27
Why would `170` round to `200` rather than `150`? `150` is closer, so it's not clear to me what rule you're using here. — Mark Dickinson, Jul 07 '21 at 14:27

score 3 · Accepted Answer · answered Jul 07 '21 at 09:27

3

Mostlikely not the cleanest way to do it but : (x + step/2)//step*step should work.

Example : print((880+25)//50*50) returns 900.

answered Jul 07 '21 at 09:27

Youenn FS

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python round numbers to specific value

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