Iterate a List and add the value to the List which is in Dictionary and clean it for every Iteration

Question

I have a python dictionary and a python list.

dictionary=
{
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":[]
}

I also have a python list,

list=["1","2","3","4"]

How Can I generate

[{
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":["1"]
},
{
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":["2"]
},
{
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":["3"]
},
{
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":["4"]
}]

Spare me If it is a silly question.

You can generate this with a loop. Please update your question with the code you have tried. — quamrana, Jul 07 '21 at 16:55
This might help: https://stackoverflow.com/questions/36536171/zip-list-with-a-single-element — styvane, Jul 07 '21 at 16:58

score 1 · Answer 1 · answered Jul 07 '21 at 16:57

there's a few steps and some ideas here, but broadly

start a fresh list to pack the final results into
iterate over the list (lists are already iterable)
copy the dict at each cycle (otherwise it'll manipulate the original one)

list_dest = []
for member in list_src:
    sub_dict = dict_src.copy()  # must copy.deepcopy for deeper members
    sub_dict["Test"] = [member]  # new list with only the list member
    list_dest.append(sub_dict)

# list_dest is now the desired collection

additionally

don't override builtins like list, as it can become confusing when you attempt to reference them later
if you wanted to get more depth than the top contents of the source dict, you should use copy.deepcopy(), or you'll still have references to the original members

Samir Ahmane · Answer 2 · 2021-07-07T17:12:54.903

An easy way to do this in short line is the following code:

my_list = ["1","2","3","4"]
dictionary={"a":"A","b":"B","c":"C","Test":[]}

list_of_dictionnaries = []

for e in my_list:
    dictionary["Test"] = [e]
    list_of_dictionnaries.append(dictionary.copy())

print(list_of_dictionnaries)

list is a built-in function, you should never name your variables as built-in functions, instead, name it something like my_list, or my_indices.

score 0 · Answer 3 · answered Jul 07 '21 at 16:58

This should work:

dictionary= {
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":[]
}
list=["1","2","3","4"]

result = []
for item in list:
    single_obj = dictionary.copy()
    single_obj["Test"] = [item]
    result.append(single_obj)

print(result)

Output:

[
   {
      "a":"A",
      "b":"B",
      "c":"C",
      "Test":[
         "1"
      ]
   },
   {
      "a":"A",
      "b":"B",
      "c":"C",
      "Test":[
         "2"
      ]
   },
   {
      "a":"A",
      "b":"B",
      "c":"C",
      "Test":[
         "3"
      ]
   },
   {
      "a":"A",
      "b":"B",
      "c":"C",
      "Test":[
         "4"
      ]
   }
]

You shouldn't name a list list in pyhton as it is a built-in function — serax, Jul 07 '21 at 17:01

score 0 · Answer 4 · answered Jul 07 '21 at 16:59

You can do something like this:

dictionary={
 "a":"A",
 "b":"B",
 "c":"C",
 "Test":[]
}
l_=[]
list2=["1","2","3","4"]
for i in list2:
    dict1=dictionary.copy() #==== Create a copy of the dictionary 
    dict1['Test']=[i] #=== Change Test value of it.
    l_.append(dict1) #=== Add the dictionary to l_
print(l_)

score 0 · Answer 5 · answered Jul 08 '21 at 19:02

0

d = {c: c.upper() for c in 'abc'}
L = [d.copy() for _ in range(4)]
for i, d in enumerate(L):
    d['Test'] = [str(i+1)]

answered Jul 08 '21 at 19:02

Lars

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Iterate a List and add the value to the List which is in Dictionary and clean it for every Iteration

5 Answers5