How do I check that the radio button values are not changed in the inspector using PHP?

Question

I have attempted using this PHP

if ($_POST['use'] != 'Photo/Video Editing' || $_POST['use'] != 'Gaming' || $_POST['use'] != 'General Purpose' || $_POST['use'] != 'Streaming') {
  echo "<p>You have changed the options - Input Invalid</p>";
} else
//Run what would normally happen

for this HTML

  <fieldset class="qwrapper">
          <legend class="ctext">What is the main use case for your computer?</legend>
          <input required  type="radio" name="use" value="Photo/Video Editing"> Photo/Video Editing
          <br>
          <input required  type="radio" name="use" value="Gaming"> Gaming
          <br>
          <input required  type="radio" name="use" value="General Purpose"> General Purpose
          <br>
          <input required  type="radio" name="use" value="Streaming"> Media Machine
          <br>

        </fieldset>

This code results in the php echoing 'You changed the options - input invalid' even when I haven't actually changed the values in the inspector to test.

you are checking with `||` equals to `OR`. so it will always fail — Sysix, Jul 08 '21 at 22:45
@Sysix what do you mean? I thought I should use || because it cannot be all 4 options at once. What other operator should I use? — Sai Sohan Gogineni, Jul 08 '21 at 22:50
Your condition will always be true. If it's equal to one value, then it's not equal to the other values, so those parts of the condition will be true. — Barmar, Jul 08 '21 at 22:54
check part by part, is the first condition false? Yes, because it has "Pohto/Video Editing". Then go to your next condition, it must be true, because the first one was already false. — Sysix, Jul 08 '21 at 22:56
A check like this should probably rather use https://www.php.net/manual/en/function.in-array.php to begin with. — CBroe, Jul 09 '21 at 07:05

How do I check that the radio button values are not changed in the inspector using PHP?

0 Answers0