I want to remove a specific element and its duplicates from a list in python 3.8

Question

l1=[int(i) for i in input().split(" ")]
itemToRemove=int(input())
for i in l1:
    if i == itemToRemove:
        l1.remove(i)
print(l1)

input: 1 2 2 2 3 4
       2

output:1 2 3 4

but the expected output should be

output:1 3 4

How could I fix this?

Take a look at this link for the some approches: https://stackoverflow.com/questions/1157106/remove-all-occurrences-of-a-value-from-a-list — KetZoomer, Jul 11 '21 at 15:25

KetZoomer · Answer 1 · 2021-07-11T15:24:03.853

You're changing the list while iterating over it. This is never a good idea. A better idea would be to use a while loop that ran whenever the element is in the list. Then, you could remove the element.

Code:

l1=[int(i) for i in input().split(" ")]
itemToRemove=int(input())

while itemToRemove in l1:
    l1.remove(itemToRemove)

print(l1)

If you want to do it with a for loop, iterate over a copy of a list:

l1=[int(i) for i in input().split(" ")]
itemToRemove=int(input())
for i in l1.copy():
    if i == itemToRemove:
        l1.remove(i)
print(l1)

You can also iterate over the number of times the itemToRemove is in l1.

l1=[int(i) for i in input().split(" ")]
itemToRemove=int(input())
for _ in range(l1.count(itemToRemove)):
    l1.remove(itemToRemove)
print(l1)

score 0 · Answer 2 · answered Jul 11 '21 at 15:31

0

The easiest method is to use while loop to compare:

l1=[int(i) for i in input()]
itemToRemove=int(input())
while itemToRemove in l1: l1.remove(itemToRemove)
print (l1)

answered Jul 11 '21 at 15:31

yogender

496
4
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I want to remove a specific element and its duplicates from a list in python 3.8

2 Answers2