How to run the second line first and then the first line in javascript?

Question

I have two log then I want first log(2) and then run log(1)

console.lo(1);
console.log(2);

END == > 2,1 in log

Answer 1

You should use promise and learn about it;

 setTimeout(async () => {
       console.log(1)
      }, 100);
       console.log(2)

Answer 2

JavaScript works from top to bottom, the easiest way to achieve what you are looking for is to change the positions

console.lo(2); console.log(1);

Answer 3

You can simply use setTimeout and run the callback function after a certain interval of time.

You should also see Why is setTimeout(fn, 0) sometimes useful?

setTimeout(_ => console.log(1), 0);
console.log(2);