How to get complete current url for Cakephp

Question

How do you echo out current URL in Cake's view?

score 89 · Accepted Answer · edited Jun 20 '20 at 04:37

89

You can do either

From a view file:

<?php echo $this->request->here() ?>">

Which will give you the absolute url from the hostname i.e. /controller/action/params

Or

<?php echo Router::url(null, true) ?>

which should give you the full url with the hostname.

edited Jun 20 '20 at 04:37

space97

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answered Jul 29 '11 at 15:18

Abba Bryant

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Side note from my experience (CakePHP 2+, not sure about the rest...) - you should use `Router::url(null, true)` instead of using `$this->here`. The reason is that if you ever have to configure a hardset base path $this->here will contain it already and your links will be double routed and broken. Just wanted to pass that along - confused the hell out of me tonight. – jocull Jan 20 '12 at 03:17
3

Also, in cake2.x `$this->here` would not be enough anymore. You would need to use `$this->here()` as this also appends the query string (and thus would then form the complete url). – mark Jan 16 '13 at 09:08
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@mark, what version are you on in 2.x? I'm in 2.4.5 and I get `PHP Fatal error: Call to undefined method MyController::here()` when I try to use the `here()` method. – Tyler Collier Jul 29 '14 at 16:10
5

Probably $this->request->here() ;) – mark Jul 29 '14 at 17:04
Please note that this doesn't contain the request URI – Alonso Urbano Nov 08 '17 at 18:40
Personally I needed the URL without the base buth with any parameters passed to the controller. A way to solve that is using `$this->getRequest()->getUri()->getPath()` (CakePHP 3 and 4). – Axel Köhler Jan 19 '22 at 10:09

score 54 · Answer 2 · edited Jul 25 '15 at 14:51

54

I prefer this, because if I don't mention "request" word, my IDE gives warning.

<?php echo $this->request->here; ?>

API Document: class-CakeRequest

Edit: To clarify all options

Current URL: http://example.com/en/controller/action/?query=12

// Router::url(null, true)
http://example.com/en/controller/action/

// Router::url(null, false)
/en/controller/action/

// $this->request->here
/en/controller/action/

// $this->request->here()
/en/controller/action/?query=12

// $this->request->here(false)
/en/controller/action/?query=12

// $this->request->url
en/controller/action

// $_SERVER["REQUEST_URI"]
/en/controller/action/?query=12

// strtok($_SERVER["REQUEST_URI"],'?');
/en/controller/action/

edited Jul 25 '15 at 14:51

Hasan Fathi

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answered Aug 06 '13 at 08:56

trante

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Thank you! You're a life saver. – crownlessking Aug 06 '17 at 01:05
My CakePHP project runs on the `localhost://projectname` URL (`projectname` folder in LAMPP stack), but using `$_SERVER["REQUEST_URI"]` doesn't include the `prohjectname` part. Any way to fix that? – Axel Köhler Jun 17 '21 at 16:58

JJJ · Answer 3 · 2011-07-26T22:13:49.077

27

<?php echo $_SERVER[ 'REQUEST_URI' ]; ?>

EDIT: or,

<?php echo $this->Html->url( null, true ); ?>

edited Jul 26 '11 at 22:13

answered Jul 26 '11 at 21:52

JJJ

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There's no "Cake way" for everything that can be done simply with basic PHP :) I guess you could do `echo $this->Html->url( null, true );` – JJJ Jul 26 '11 at 22:09

Costa · Answer 4 · 2013-01-16T03:42:25.913

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The following "Cake way" is useful because you can grab the full current URL and modify parts of it without manually having to parse out the $_SERVER[ 'REQUEST_URI' ] string and then manually concatenating it back into a valid url for output.

Full current url:
Router::reverse($this->request, true)

Easily modifying specific parts of current url:
1) make a copy of Cake's request object: $request_copy = $this->request

2) Then modify $request_copy->params and/or $request_copy->query arrays

3) Finally: $new_url = Router::reverse($request_copy, true).

edited Jan 16 '13 at 03:42

answered Nov 15 '12 at 02:56

Costa

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Ooos, forgot the `true` parameter. Updated answer. – Costa Jan 16 '13 at 03:45

AndreyP · Answer 5 · 2020-09-07T11:34:00.630

10

Cakephp 3.5:

echo $this->Url->build($this->getRequest()->getRequestTarget());

Calling $this->request->here() is deprecated since 3.4, and will be removed in 4.0.0. You should use getRequestTarget() instead. $this->request is also deprecated, $this->getRequest() should be used.

edited Sep 07 '20 at 11:34

answered Aug 14 '17 at 15:04

AndreyP

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A comment on the accepted answer might have sufficed :) – mark Aug 14 '17 at 15:25
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Or `$this->getRequest()->getRequestTarget()` to be even more deprecation-proof :D – ᴍᴇʜᴏᴠ Sep 07 '20 at 11:32

score 6 · Answer 6 · answered Apr 02 '12 at 08:15

I know this post is a little dated, and CakePHP versions have flourished since. In the current (2.1.x) version of CakePHP and even in 1.3.x if I am not mistaken, one can get the current controller/view url like this:

$this->params['url'];

While this method does NOT return the parameters, it is handy if you want to append parameters to a link when building new URL's. For example, we have the current URL:

projects/edit/6

And we want to append a custom parameter action called c_action with a value of remove_image, one could make use of $this->params['url]; and merge it with an array of custom parameter key => value pairs:

echo $this->Html->link('remove image', array_merge($this->params['url'], array('c_action' => 'remove_image'));

Using the above method we are able to append our custom parameters to the link and not cause a long chain on parameters to build up on the URL, because $this->params['url] only ever returns the controll action URL.

In the above example we'd need to manually add the ID of 6 back into the URL, so perahaps the final link build would be like this:

echo $this->Html->link('remove image', array_merge($this->params['url'], array($id,'c_action' => 'remove_image'));

Where $is is a the ID of the project and you would have assigned it to the variable $id at controller level. The new URL will then be:

projects/edit/6/c_action:remove_image

Sorry if this is in the slightest unrelated, but I ran across this question when searching for a method to achieve the above and thought others may benefit from it.

You can just do `echo $this->Html->link('remove image', array('action' => 'remove_image'))`. I'm not sure if that is a functionality from later than 2.1.x, but that should work. Unless you overwrite the controller key in the array, the current controller will be used. — Jelmer, Dec 14 '13 at 18:54
or `$this->request->url` for url including `query` and `named` params — Fr0zenFyr, Jul 10 '19 at 07:28

score 5 · Answer 7 · edited May 23 '17 at 12:26

Getting the current URL is fairly straight forward in your view file

echo Router::url($this->here, true);

This will return the full url http://www.example.com/subpath/subpath

If you just want the relative path, use the following

echo $this->here;

OR

Ideally Router::url(“”, true) should return an absolute URL of the current view, but it always returns the relative URL. So the hack to get the absolute URL is

$absolute_url  = FULL_BASE_URL + Router::url(“”, false);

To get FULL_BASE_URL check here

score 5 · Answer 8 · answered Sep 08 '14 at 12:14

5

for CakePHP 3:

$this->Url->build(null, true) // full URL with hostname

$this->Url->build(null) // /controller/action/params

answered Sep 08 '14 at 12:14

Alex Stallen

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score 5 · Answer 9 · edited Nov 28 '16 at 16:49

5

Getting current URL for CakePHP 3.x ?

In your layout :

<?php 
    $here = $this->request->here();
    $canonical = $this->Url->build($here, true);
?>

You will get the full URL of the current page including query string parameters.

e.g. http://website.example/controller/action?param=value

You can use it in a meta tag canonical if you need to do some SEO.

<link rel="canonical" href="<?= $canonical; ?>">

edited Nov 28 '16 at 16:49

Faisal

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answered Apr 05 '16 at 08:53

Guillaume

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1

Note: here() has been deprecated as of CakePHP 3.4.0 in favor of getRequestTarget() – Phantom Watson Jul 28 '18 at 22:22

score 3 · Answer 10 · answered Mar 05 '14 at 13:40

3

In the request object you have everything you need. To understand it:

debug($this->request->url);

and in your case

$here = $this->request->url;

answered Mar 05 '14 at 13:40

gdm

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this one helped me out.. also that of "trante" – Rizwan Sohaib Sep 03 '14 at 16:59

score 3 · Answer 11 · answered May 11 '17 at 09:28

3

To get the full URL without parameters:

echo $this->Html->url('/', true);

will return http(s)://(www.)your-domain.com

answered May 11 '17 at 09:28

Thomas Rbt

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score 3 · Answer 12 · answered Dec 26 '18 at 07:05

After a few research, I got this as perfect Full URL for CakePHP 3.*

$this->request->getUri();

the Full URL will be something like this

http://example.com/books/edit/12

More info you can read here: https://pritomkumar.blogspot.com/2017/04/how-to-get-complete-current-url-for.html

score 2 · Answer 13 · answered Dec 31 '17 at 10:43

The simplest way I found is it that includes host/path/query and
works in Controllers (Cakephp 3.4):

Cake\View\Helper\UrlHelper::build($this->request->getRequestTarget());

which returns something like this (we use it as login callback url) :

http://192.168.0.57/archive?melkId=12

Steve Tauber · Answer 14 · 2015-07-26T20:46:38.033

1

The Cake way for 1.3 is to use Router::reverse:

Link to documentation

$url = Router::reverse($this->params)
echo $url;

yields

/Full/Path/From/Root/MyController/MyAction/passed1/named_param:bob/?param1=true&param2=27

edited Jul 26 '15 at 20:46

answered Dec 13 '12 at 00:16

Steve Tauber

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score 1 · Answer 15 · answered Jan 05 '16 at 18:56

1

Cakephp 3.x anywhere:

Router::reverse(Router::getRequest(),true)

answered Jan 05 '16 at 18:56

Amorphous

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score 1 · Answer 16 · answered Mar 07 '16 at 23:06

for CakePHP 3.x You can use UrlHelper:

$this->Url->build(null, true) // output http://somedomain.com/app-name/controller/action/params

$this->Url->build() // output /controller/action/params

Or you can use PaginatorHelper (in case you want to use it in javascript or ...):

$this->Paginator->generateUrl() // returns a full pagination URL without hostname

$this->Paginator->generateUrl([],null,true) // returns a full pagination URL with hostname

score 1 · Answer 17 · answered May 19 '16 at 03:17

1

for cakephp3+:

$url = $this->request->scheme().'://'.$this->request->domain().$this->request->here(false);

will get eg: http://bgq.dev/home/index?t44=333

answered May 19 '16 at 03:17

Cao Vison

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score 1 · Answer 18 · answered May 09 '17 at 18:14

In View:

Blank URL: <?php echo $this->Html->Url('/') ?>
Blank Full Url: <?php echo $this->Html->Url('/', true) ?>
Current URL: <?php echo $this->Html->Url($this->here) ?>
Current Full URL: <?php echo $this->Html->Url($this->here, true) ?>

In Controller

Blank URL: <?php echo Router::url('/') ?>
Blank Full Url: <?php echo Router::url('/', true) ?>
Current URL: <?php echo Router::url($this->request->here()) ?>
Current Full URL: <?php echo Router::url($this->request->here(), true) ?>

$this->Html->Url != $this->Html->url – mark May 09 '17 at 19:11 — mark, May 09 '17 at 19:11

score 0 · Answer 19 · answered Oct 21 '12 at 13:55

All previously proposed approaches didn't satisfy my requirements for getting a complete URL (complete as in qualified) e.g. to be used in an email send from controller action. I need the scheme and hostname as well then, and thus stumbled over the following approach:

<?php echo Router::url( array( $id ), true ) ?>

Due to providing router array current controller and action is kept, however id isn't and thus has to be provided here again. Second argument true is actually requesting to prepend hostname etc. for getting full URL.

Using Router::url() is available in every situation and thus can be used in view files as well.

score 0 · Answer 20 · answered Apr 01 '14 at 19:42

0

Yes, is easy FULL URL in Controler Work in CakePHP 1.3 >

<?php echo Router::url( array('controller'=>$this->params['controller'],'action'=>$this->params['action']), true );

Saludos

answered Apr 01 '14 at 19:42

User

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score 0 · Answer 21 · answered Nov 23 '16 at 02:34

0

Use Html helper

<?php echo $this->Html->url($this->here, true); ?>

It'll produce the full url which'll started from http or https

answered Nov 23 '16 at 02:34

Samphors

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score 0 · Answer 22 · edited Jul 10 '18 at 10:30

0

In CakePHP 3 $this->here will be deprecated. The actual way is using this method:

Router::url($this->request->getRequestTarget())

edited Jul 10 '18 at 10:30

Andrej Kesely

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answered Jul 10 '18 at 09:04

Oliwer Lisek

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score 0 · Answer 23 · answered Apr 22 '20 at 06:28

0

For CakePHP 4.*

echo $this->Html->link(
    'Dashboard',
    ['controller' => 'Dashboards', 'action' => 'index', '_full' => true]
);

answered Apr 22 '20 at 06:28

hasentopf

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score 0 · Answer 24 · answered Apr 19 '21 at 12:14

If you want to return the base path, you can check that the Router class is using Configure::read ('App.fullBaseUrl'). So if you are a fan of hexagonal architecture, you can create a Cake implementation for creating URLs that will only use Configure from all CakePHP framework.

score 0 · Answer 25 · answered Jul 27 '11 at 08:39

0

I use $this->here for the path, to get the whole URL you'll have to do as Juhana said and use the $_SERVER variables. There's no need to use a Cake function for this.

answered Jul 27 '11 at 08:39

Dunhamzzz

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How to get complete current url for Cakephp

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