How to deal with 'await' outside async function?

Question

The below function is calling the create_presigned_url but I am getting an error in await.

 def getPreSignedURL(request: Request, file: UploadFile = File(...) ):
       resp = await create_presigned_url(request,file)
       return resp

this is an async function which I want to call

async def create_presigned_url(bucket_name, object_name, expiration=3600):
---
return response

you can not call an async method from a sync method. for more info https://stackoverflow.com/questions/55647753/call-async-function-from-sync-function-while-the-synchronous-function-continues — Vivek Singh, Jul 14 '21 at 04:23
You cannot call an async function from the regular function as described above. You would need to use asyncio. — tomarv2, Jul 14 '21 at 04:27

tomarv2 · Accepted Answer · 2021-07-14T06:06:06.040

6

Hope this helps. Example of calling async function from regular function:

import asyncio

loop = asyncio.get_event_loop()


async def demo(name):
    return f"hello {name}"


def main():
    result = loop.run_until_complete(demo("world"))
    print(result)


if __name__ == '__main__':
    main()

edited Jul 14 '21 at 06:06

answered Jul 14 '21 at 04:47

tomarv2

753
3
14

Yes, I did it, I was missing async before function declaration, that has resolved the issue. Thanks for helping – sakshi singhal Jul 14 '21 at 08:49
@sakshisinghal If you agree with the answer do you mind up voting it. – tomarv2 Jul 15 '21 at 04:12

How to deal with 'await' outside async function?

1 Answers1