Generate non-duplicate random number array JS 2nd

Question

I asked this question 2nd time because 1st time someone closed my question and I didn't get 1 satisfactory answer. Please read my question carefully

i am trying to create an array where random elements do not overlap when i load the page for the first time, but it crashes what should i do?

first i want to generate random number from 1-10....but how to generate this if i want to change from 1-20 and take only 10 non-matching numbers? my random numbers may vary in random range, not fixed from 1-10, take a look at my code above

I don't intend to randomly ask for a number from a given array

  $(window).on('load', function () {
            const a = [];
           
            for(let i = 0; a.length < 10;){
                let b = Math.floor(Math.random() * 10) + 1;
                if(a.indexOf(b) === -1){
                    a.push(b);

                }
            }
        })

what I want above when I change C to 20, it will be random 1-20, C= 30=> random 1-30

Don't post your question a second time. Edit your first question in such a way that it is clear that it is not a duplicate (I suppose that is your point?). Posting it again is counter productive. — trincot, Jul 17 '21 at 16:44
What do you want to do with `a`? It will be out of scope when the function ends, so even if the function worked it wouldn't do anything. — MikeM, Jul 17 '21 at 16:55
a will be an array with elements that do not match the variable range c — Thắng Trương Khắc, Jul 17 '21 at 16:57
What is the variable `i` for? Better: `while (a.length < 10) {` — MikeM, Jul 17 '21 at 17:00
i run from array a = 0, run until array a is full (ie random is enough), the 3rd parameter i don't know what should be set — Thắng Trương Khắc, Jul 17 '21 at 17:02
You don't need `i`. You can use `for (; a.length < 10;) {` or `while` as shown above. — MikeM, Jul 17 '21 at 17:04

Generate non-duplicate random number array JS 2nd

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