XML to XSD tool for linux

Question

What's the best tool out there to create (or to infer) an XSD schema from XML document? I need it to be linux-compatible.

Hmm, how would that work? XSD is extremely semantic, and that's something you can't infer from examples. — Šimon Tóth, Jul 27 '11 at 11:20
I have a simply XML response, and I want to create, based on this XML, a XSD schema. I've found some tools online, like http://www.flame-ware.com/products/xml-2-xsd/ , but I'd like to know if there's something better... — Aitor, Jul 27 '11 at 11:25
On windows this is easy as there is a tool in the .net SDK, sorry don't know about unix — Ian Ringrose, Jul 27 '11 at 12:15
@Let_M_Be, in a lot of cases a tool can create a good enough XSD for a example XML document. A set of classes for read/writing the xml can them be auto created from the XSD (maybe with a bit of hand editing of the XSD if needed) — Ian Ringrose, Jul 27 '11 at 12:16
@Let_M_Be: When creating XSD's, It's a huge time saver. First I get some XML examples, and *convert* to respective XSD's. Then I combine the appropriate parts together, and make some hand edits, to make the final XSD. It's never 100%, as it only covers the your original XML input, but that does not make the process worthless. — J. M. Becker, Dec 16 '12 at 17:38

score 20 · Accepted Answer · answered Aug 21 '11 at 23:02

20

Its old and basic but i find it generates cleaner schemas than other tools (e.g. XMLSpy)

answered Aug 21 '11 at 23:02

Sam

Finally, trang is the tool we're using to transform a XSD in a DTD, and also the reverse. Thanks! – Aitor Dec 17 '12 at 11:33
10

On Ubuntu : sudo apt-get install trang ; trang input.xml output.xsd – rjdkolb Jan 25 '16 at 12:04
This seems to work well. Usage: trang -I xml -O xsd example.xml schema.xsd – Aaron Swan Feb 03 '20 at 20:12

score 3 · Answer 2 · edited May 23 '17 at 12:02

3

You can create a DTD from XML using DTDGenerator from the saxon project. Then you can convert this to a XSD using W3C's dtd2xsd.pl. See Free DTD to XSD conversion utility?.

edited May 23 '17 at 12:02

Community

answered Jul 27 '11 at 11:25

marc

Thank you.. Perhaps it's a better method convert to DTD and then to XSD than directly to a XSD. – Aitor Jul 27 '11 at 12:10
Wouldn't XML->XSD generally be better than XML->DTD->XSD since XSD is potentially more descriptive? The latter could lead to a less specific XSD. – David Moreau Jul 19 '21 at 14:34

2 Answers2