Else If statement with numbers

Question

My code does not seem to be working and I'm not sure why, I'm knew to else if statements so maybe I'm doing this completely wrong. I need the user to enter a number and depending on the number they enter a statement is printed out.

Please see my code below, the error message I'm getting is "Undefined" after the user enters the number and presses enter.

let waterPay = prompt("Please enter the amount of water you use to get a price you need to pay, thank you!");

if (waterPay > 6000) {
  console.log("The number is below 6000");
} else if (waterPay(6000 <= 10500)) {
  console.log("The number is between 6000 and 10500");
} else if (waterPay(10.5 <= 35000)) {
  console.log("The number is between 10500 and 35000");
} else(waterPay( <= 35000)) {
  console.log("The number is above 35000");
}

You should use```(waterPay > 6000 && waterPay <= 10500)``` instead — ikhvjs, Jul 19 '21 at 10:04
I'd suggest skimming some JS tutorials or looking around for what if-statement expressions look like--only one of these is correct. — Dave Newton, Jul 19 '21 at 10:05
huuh?`if (waterPay > 6000) {console.log("The number is below 6000");}` shouldn't this be ""The number is above 6000"" — I_love_vegetables, Jul 19 '21 at 10:05
"_I'm getting is "Undefined" after the user enters the number and presses enter._" If you're using the code above, I highly doubt that you get prompted anything at all. It contains several syntax errors. — Ivar, Jul 19 '21 at 10:06

score 0 · Answer 1 · answered Jul 19 '21 at 10:07

From a quick look, it seems that the if-else-if is structured correctly. There appears to be an issue with your comparisons though. For example waterPay (6000 <= 10500) is not valid syntax. You probably want to write waterPay > 6000 && waterPay < 10500

Also make sure all your branches are accessible, ie that conditions don’t overlap

ksav · Answer 2 · 2021-07-20T07:24:54.870

0

Check out the if...else page on mdn to see the expected syntax.

let waterPay = prompt("Please enter the amount of water you use to get a price you need to pay, thank you!");

if (waterPay < 6000) {
  console.log("The number is below 6000");
} else if (waterPay <= 10500) {
  console.log("The number is between 6000 and 10500");
} else if (waterPay <= 35000) {
  console.log("The number is between 10501 and 35000");
} else {
  console.log("The number is above 35001");
}

edited Jul 20 '21 at 07:24

answered Jul 19 '21 at 10:08

ksav

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`(waterPay <= 10500)` should be `(waterPay > 6000 && waterPay <= 10500)` – I_love_vegetables Jul 19 '21 at 10:10
1

@Anonymouse If `waterPay < 6000`, the if-block will be entered and the `else if (waterPay <= 10500)` will never be executed. Hence the `waterPay > 6000` (or `>=` rather) is not necessary. – Ivar Jul 19 '21 at 10:14
@Ivar oh damn i how could i not realise that, i feel so dumb rn lmao – I_love_vegetables Jul 19 '21 at 10:19

Else If statement with numbers

2 Answers2