How to ignore empty string in list object?

Question

I have list object like below

0:""
1:""
3:"tag1"
4:"tag2

This is my question how to ignore empty value.I need a result like the below.

0:"tag1"
1:"tag2

Thanks for help me.

You can use `Array.prototype.filter()` to return just the non-empty strings. — Barmar, Jul 19 '21 at 20:02
https://stackoverflow.com/questions/281264/remove-empty-elements-from-an-array-in-javascript — fnostro, Jul 19 '21 at 20:03

score 1 · Answer 1 · answered Jul 19 '21 at 20:05

1

One naive solution could be:

const obj = {
  0: "",
  1: "",
  2: "tag1",
  3: "tag2"
};

const newObj = Object.fromEntries(
  Object.entries(obj).filter(([k, v]) => v)
);

Object.entries turns an object into an array of keys and values.

For example

Object.entries(obj)

becomes

[
  [
    "0",
    ""
  ],
  [
    "1",
    ""
  ],
  [
    "2",
    "tag1"
  ],
  [
    "3",
    "tag2"
  ]
]

which is then filtered by whether the value is "truthy"

.filter(([k,v]) => v))

and finally turned back into an object

Object.fromEntries

answered Jul 19 '21 at 20:05

evolutionxbox

did you mean native or naive? – Kinglish Jul 19 '21 at 20:10
@Kinglish definitely naive. My answer isn't super comprehensive, and does not take edge-cases into consideration. – evolutionxbox Jul 19 '21 at 20:42

score 1 · Answer 2 · answered Jul 19 '21 at 20:07

1

If that is an array, you can use filter.

let o = ["","",,"tag1","tag2"];
let res = o.filter(Boolean); // or o.filter(x => x);
console.log(res);

To be more precise, you could use:

let res = o.filter(x => x !== '');

answered Jul 19 '21 at 20:07

Unmitigated

2 Answers2