how can i make multiple loops?

Question

I am facing a problem with java array loops well, this is the problem

Use the space below to write main method that reads 5 integer values into an array named list. Then, use the array to output the positive values followed by the negative values and ignore zeros.

Sample Output
Enter 5 numbers: 10 -3 0 -4 9
List: 
10
9
-3
-4

and this is the answer:

int [] list = new int[5];
// 1pt
Scanner read = new Scanner (System.in);

// 3pts
System.out.println("Enter 5 numbers:");
for (int i = 0; i < list.length; i++)
    list[i] = read.nextInt();

// 3 pts
for (int i = 0; i < list.length; i++)
    if (list[i] > 0)
        System.out.println(list[i]);

// 3 pts
for(int i = 0; i < list.length; i++)
    if (list[i] < 0)
        System.out.println(list[i]);

but i do not know how to make them work together if you get me

by combining the logic of the last two loops in one. or by just using one single loop. use a StringBuilder to build the output, which you only print after completion of your loop(s) — Stultuske, Jul 20 '21 at 07:29

score 0 · Answer 1 · answered Jul 20 '21 at 17:54

The easiest way to do using Java8 can be this

    Integer [] list = new Integer[5];
    Scanner read = new Scanner (System.in);
    System.out.println("Enter 5 numbers:");
    for(int i=0; i<list.length;i++)
     list[i] = read.nextInt();

    List<Integer> newList = Arrays.asList(list).stream().filter(x -> x !=0).collect(Collectors.toList());
    Collections.sort(newList,(a,b) -> {
        if(a>b)
            return -1;
        else if(b>a)
            return 1;
        else 
            return 0;
    });
    System.out.println(newList);

score 0 · Answer 2 · answered Jul 22 '21 at 09:15

You can use Stream filter() in java to get elements according to your need here we will check that value is not equal to zero (s-> s != 0) and here we are using lambdas in java 8.

    int [] list = new int[5];
    Scanner read = new Scanner (System.in);
    System.out.println("Enter 5 numbers:");
    for (int i = 0; i < list.length; i++) {
      list[i] = read.nextInt();
      if(i == 4)
        list = (Arrays.stream(list).filter(s -> s != 0).toArray());
    }
    System.out.println(Arrays.toString(list));

Java Stream filter() , filter array using lambda

score 0 · Accepted Answer · answered Jul 23 '21 at 10:40

You can use the following code snippet to sort the array and then later display it and put a condition in between which checks whether an element of the array is 0 or not.

    for(int i = 0 ; i <= 5 ; i++){
        if(i < 5){
            System.out.println("Enter 5 numbers:");
            for (int i = 0; i < list.length; i++)
                list[i] = read.nextInt();
            continue;
        }
        for(int j = i ; i < 10 ; j++){
            if(list[i] > list[j]){
                int temp = list[i] ;
                list[i] = list[j] ;
                list[j] = temp ;
            }
        }
        if(i == 5){
            for(int j = 0; j < 5; j++){
                if(list[i] != 0)
                    System.out.println(list[i]);
            }
        }
    }

I guess this is what you want.

how can i make multiple loops?

3 Answers3